AQA GCSE Chemistry (8462) · Paper 1

⚖️ Quantitative Chemistry

Revision notes written to the specification, with examiner tips and the required practicals. Every point here has flashcards in the Stickwise app.

Conservation & Mr

Conservation of mass means that no atoms are created or destroyed in a chemical reaction, they are only rearranged. This means the total mass of the reactants always equals the total mass of the products.

A balanced symbol equation shows the same number of atoms of every element on both sides of the equation. It is balanced by changing only the large numbers in front of each formula, called coefficients, and never the small subscripts within a formula, since changing a subscript would change the substance itself.

Questions about an apparent change in mass usually involve a gas. In an open container, mass can seem to fall because a gas has escaped, for example when a carbonate gives off CO₂, or mass can seem to rise because a gas has been taken in from the air, for example when a metal gains oxygen. In both cases the atoms are all still there; the balance simply cannot detect the gas that has left or joined the reaction.

Relative formula mass (Mr)The relative formula mass (Mr) is found by adding up the Ar of every atom in the formula. For H₂O this is 1+1+16 = 18, and for CO₂ it is 12+16+16 = 44.
UncertaintyAny measurement has a range within which the true value might really lie, so a result is quoted as the measured value ± half that range.
% mass of an element = (Ar × number of atoms ÷ Mr) × 100 — e.g. H in H₂O: 2⁄18 ≈ 11%

Moles & concentration

Higher tier only

For higher tier, the mole is chemistry's counting unit, equal to 6.02 × 10²³ particles, a number known as the Avogadro constant. One mole of any substance weighs its Mr in grams, so one mole of water weighs 18 g.

moles = mass ÷ Mr (rearranged: mass = moles × Mr)
Higher tier only

For higher tier, reacting mass calculations follow three steps.

For example, in the equation 2Mg + O₂ → 2MgO, 1 mole of Mg produces 1 mole of MgO.

Higher tier only

For higher tier, the limiting reactant is the reactant that runs out first, and it decides how much product can form. Every other reactant is described as being in excess, and calculations should be scaled from the limiting reactant.

concentration (g/dm³) = mass of solute ÷ volume of solution
🎯 Examiner tip: 1 dm³ equals 1000 cm³, which in turn equals 1 litre. Always convert a volume from cm³ to dm³, by dividing by 1000, before using it in a concentration formula — forgetting this conversion is the most common lost mark in this topic.

Yield, economy & titrations Separate science only

% yield = mass actually made ÷ maximum theoretical mass × 100

Yield is usually below 100% because reactions can be reversible, some product is lost during transfers and separations, and side reactions use up some of the reactants without forming the desired product.

atom economy = Mr of desired product ÷ total Mr of all products × 100

Atom economy measures how much of the mass of the reactants ends up in the desired product. A high atom economy means less waste, so the process is greener and more profitable, and a reaction with only one product has an atom economy of 100%.

Higher tier only

For higher tier, concentration in mol/dm³ can be converted to g/dm³ using the Mr: g/dm³ = mol/dm³ × Mr.

For Triple Science, one mole of any gas occupies 24 dm³ at room temperature and pressure.

Titrations (Triple Science)

🧪 Required practical: In a titration, a pipette is used to measure a fixed volume of alkali into a conical flask, and a few drops of indicator are added. Acid is then run in from a burette, with swirling, until the colour just changes at the end point. The burette should be read to the nearest 0.05 cm³, and the titration should be repeated until two or more concordant results, meaning results within 0.10 cm³ of each other, are obtained, so that a mean can be calculated.
Higher tier only

For higher tier, the calculation for a titration follows the same three-step pattern as reacting masses, and setting out each step clearly, with its units, makes it straightforward to follow.

Turn these notes into memory. 19 flashcards cover this topic. Short daily sessions, spaced repetition up to your exam date, quizzes with friends. Free during the beta.Practise Quantitative Chemistry in the app ↗